If x + y + z = 19, xyz = 216 and xy + yz + zx = 114, then the value of √(x 3 + y 3 + z 3 + xyz) is:

SSC CHSL 1 July 2019 Shift 3 Paper

Question : 57 of 100

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If x + y + z = 19, xyz = 216 and xy + yz + zx = 114, then the value of √(x³+ y³+ z³+ xyz) is:

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