If 1 + 2tan 2 θ + 2sinθ sec 2 θ = \frac{a}{b}. 0° < θ < 90°, then \frac{a + b}{a−b} = ?

SSC CGL Tier II Quant 29 Jan 2022 Paper

Question : 11 of 100

Marks: +1, -0

If 1 + 2tan²θ + 2sinθ sec²θ =

\;{a}/{b}

. 0° < θ < 90°, then

\;{a\;+\;b}/{a−b}

= ?

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