Let the probability function of X be given by p(x)={\\begin{array}{c}\\\{18\end\frac{array}{38}, x=.5 ; \frac{18}{38}, x=1 ; \frac{2}{38}, x=10 ; 0, \text{ otherwise }}. Then P(0 ≤ X ≤ 2) is equal to:

SSC CGL Tier II (JSO) 4 March 2023 Paper

Question : 44 of 100

Marks: +1, -0

Let the probability function of X be given by

p(x)={\{\table \;{18}/{38}, x=.5 ; \;{18}/{38}, x=1 ; \;{2}/{38}, x=10 ; 0, \;\text " otherwise "\;}.

Then P(0 ≤ X ≤ 2) is equal to:

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