SSC CGL Tier II 25 Oct 2015 Paper 1

Question : 71 of 100

Marks: +1, -0

The perimeter of a rhombus is 60 cm and one of its diagonal is 24 cm. The area of the rhombus is

Solution:

(2) Side of rhombus

= { { \Perimeter }}/{4}= {60}/{4}=15 {cm}

d_1

= AC = 24 cm.
OC = 12 cm.
CD = 15 cm.
∠COD = 90°
∴ In ΔOCD,

{OD}=√{ {CD}^{2}- {OC}^{2}}

=√{15^{2}-12^{2}}=√{225-144}

=√{81}=9 {cm} .

∴ d_{2}= {BD}=2 × 9=18 {cm}

∴Area of rhombus

= {1}/{2} d_{1} d_{2}= {1}/{2} × 24× 18

=216 {sq.} {cm}

Go to Question:

Prev Question

Next Question