SSC CGL Tier II 25 Oct 2015 Paper 1

(1) $7^1=7,7^2=49,7^3=343$ $7^4=2401,7^5=16807$
i.e. after index 4, the unit’s digit is repeated.
∴ On dividing 153 by 4, remainder = 1
∴ Unit’s digit in the expansion of ${\left(2467\right)}^{153}=7^1=7$ and
unit’s digit in the expansion of ${\left(341\right)}^{72}=1$
∴ Required unit’s digit $=7\times 1=7$