SSC CGL Tier II 25 Oct 2015 Paper 1

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Question : 38 of 100

Marks: +1, -0

A and B are centres of two circles of radii 11 cm and 6 cm, respectively. PQ is a direct common tangent to the circles. If

\ov \AB

= 13 cm, then length of

\ov \PQ

will be

8.5 cm
13 cm
12 cm
17 cm

Solution:

(3)

{PQ}=√{ {AB}^{2}- (r_{1}-r_{2} )^{2}}

=√{13^{2}-(11-6)^{2}}

=√{13^{2}-5^{2}}=√{169-25}

=√{144}=12 {\cm} .

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