SSC CGL Tier II 21 Sep 2014 Paper

Question : 51 of 100

Marks: +1, -0

If the number of items of a set A be n (A) = 40, n (B) = 26 and n (A∩B) = 16, then n (AUB) is equal to

Solution:

(3)

n (A ∩ B)

=n(A)+n(B)-n(A ∩ B)

=40+26-16=50

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