SSC CGL Tier II 21 Sep 2014 Paper

Question : 5 of 100

Marks: +1, -0

An interior angle of a regular polygon is 5 times its exterior angle. Then the number of sides of the polygon is

Solution:

(3) If the number of sides of regular polygon be n, then Each interior angle

= {(2 n-4)× 90°}/{n}

and each exterior angle

= 360°/n

∴{(2 n-4)}/{n}× 90°= {5 ×360°}/{n}

⇒(2 n-4)=5× 4

⇒ 2 n-4=20

⇒ 2 n=20+4=24

⇒ n= {24}/{2}=12

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