SSC CGL Tier II 21 Sep 2014 Paper

Question : 46 of 100

Marks: +1, -0

If sin 5 θ = cos 20° ( 0° < θ < 90°) then the value of θ is

Solution:

(4) sin 5θ = cos20°
⇒ sin 5θ = sin (90 – 20) = sin 70°
⇒ 5θ = 70°
⇒ θ =

70/5

= 14°

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