SSC CGL Tier II 21 Sep 2014 Paper

(2) Let the angles be A and B where A > B
∴ A + B = 135°
and, A – B
$=\frac{\mathrm{\pi }}{12}=\frac{\mathrm{\pi }}{12}\times \frac{180°}{\mathrm{\pi }}=15°$
On adding
A + B + A – B = 135° + 15° = 150°
⇒ 2A = 150° ⇒ A = $\frac{150}{2}$ = 75°
∴ A + B = 135°
⇒ B = 135° – 75° = 60°