SSC CGL Tier II 21 Sep 2014 Paper

Question : 34 of 100

Marks: +1, -0

In triangle ABC a straight line parallel to BC intersects AB and AC at D and E respectively. If AB = 2AD then DE : BC is

Solution:

(3)

{A B}/{A D}= {2}/{1}

\Δ A D E∼\Δ A B C

{A B}/{A D}= {B C}/{D E}= {2}/{1}

∴{D E}/{B C}= {1}/{2}

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