SSC CGL Tier II 21 Sep 2014 Paper

Question : 31 of 100

Marks: +1, -0

G is the centroid of the equilateral ΔABC. If AB = 10 cm then length of AG is

Solution:

(2)

AB = 10 cm
BD = 5 cm
∠ADB = 90°

∴ A D=√{A B^{2}-B D^{2}}

=√{10^{2}-5^{2}}=√{100-25}

=√{75}

=5 √{3} {cm}

A G= {2}/{3} A D= {2}/{3}× 5 √{3}

= {10}/{√{3}} {cm}

Go to Question:

Prev Question

Next Question