In a triangle ABC, \angle A+ \frac{1}{2} \angle B+\angleC=140^\circ,\angle B thenis

SSC CGL Tier II 21 Sep 2014 Paper

Question : 28 of 100

Marks: +1, -0

In a triangle ABC,

∠ A+ {1}/{2} ∠ B+∠C=140°,∠ B

thenis

Solution:

(2) ∠A + ∠B + ∠C = 180° ...(i)

∠ A+ {1}/{2} ∠ B+∠C=140°

By equation (i) – (ii),

{∠ B}/{2}=180°-140°

⇒{∠B}/{2}=40°

⇒∠{B}=80°

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