If {2 p}/{p^{2}-2 p+1}= \frac{1}{4} then the value of (p+ \frac{1}{p} )is

SSC CGL Tier II 12 Apr 2015 Paper

Question : 27 of 100

Marks: +1, -0

{2 p}/{p^{2}-2 p+1}=\ {1}/{4}

then the value of

(p+ {1}/{p} )

Solution:

(4)

{2 p}/{p^{2}-2 p+1}=\ {1}/{4}

On dividing numerator and denominator by p, we get,

{2}/{p-2+\ {1}/{p}}= {1}/{4}

⇒ p+ {1}/{p}-2=8

⇒ p+ {1}/{p}=8+2=10

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