SSC CGL Tier II 12 Apr 2015 Paper

Question : 12 of 100

Marks: +1, -0

The outer and inner diameter of a circular path be 728 metre and 700 metre respectively. The breadth of the path is

Solution:

. (3)

{O} {A}= {700}/{2}=350 {\metre}

{OB}= {728}/{2}=364

metre
Width of path = OB – OA = 364 – 350 = 14 metre

Go to Question:

Prev Question

Next Question