SSC CGL Tier II 1 Dec 2016 Paper 1

Question : 83 of 100

Marks: +1, -0

If D and E are the mid-points of AB and AC respectively of ΔABC, then the ratio of the areas of Δ ADE and

□

BCED is

Solution:

(4)

DE || BC and DE =

1/2

∴{ { \Area \of } \Δ {ABC}}/{ { \Area \of } \Δ {ADE}}= { {BC}^{2}}/{ {DE}^{2}}=4

∴ Area of ΔADE =

1/4

× Area of ΔABC
Area of

□

BCED =

3/4

× Area of ΔABC
∴ Required ratio = 1 : 3

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