SSC CGL Tier II 1 Dec 2016 Paper 1

Question : 73 of 100

Marks: +1, -0

The value of x which satisfies the equation

{x+a^{2}+2 c^{2}}/{b+c}+

{x+b^{2}+2 a^{2}}/{c+a }+ {x+c^{2}+2 b^{2}}/{a+b}=0

Solution:

(2) Of the given options,

x=- (a^{2}+b^{2}+c^{2} )

∴{x+a^{2}+2 c^{2}}/{b+c}

= {-a^{2}-b^{2}-c^{2}+a^{2}+2 c^{2}}/{b+c}

= {c^{2}-b^{2}}/{b+c}=c-b

{x+b^{2}+2 a^{2}}/{c+a}

=\ {-a^{2}-b^{2}-c^{2}-b^{2}+2 a^{2}}/{c+a}

= {a^{2}-c^{2}}/{c+a}=a-c

{x+c^{2}+2 b^{2}}/{a+b}

= {-a^{2}-b^{2}-c^{2}+c^{2}+2 b^{2}}/{a+b}

= {b^{2}-a^{2}}/{a+b}=b-a

∴ c-b+a-c+b-a=0

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