SSC CGL Tier II 1 Dec 2016 Paper 1

Question : 63 of 100

Marks: +1, -0

The lateral surface area of frustum of a right circular cone, if the area of its base is 16π cm

^{2}

and the diameter of circular upper surface is 4 cm and slant height is 6 cm, will be

Solution:

(3) According to the question,

\π{R}^{2}=16 \π

⇒{R}^{2}=16

⇒{R}=√{16}=4 {cm}

∴ Required area

=\π( {R}+r) l

=\π(4+2) ×6

=36 \π{\sq} . {\cm}

Go to Question:

Prev Question

Next Question