If , \frac{x^3+3x}{3x^2+1}=1027/973 , then find the value of 7x.

SSC CGL Model Paper 9

Question : 66 of 100

Marks: +1, -0

If ,

{x^3+3x}/{3x^2+1}=1027/973 ,

then find the value of 7x.

Solution:

{x^3+3x}/{3x^2+1}=1027/973

By C-D RULE

{x^3+ 3 x + 3 x^2+ 1 }/{x^3+3x-3x^2- 1}={1027+973 }/{1027-973 }

(x+1)^3/(x-1 )^3=2000/54

({x + 1}/{x- 1})^3=1000/27

{x + 1}/{x + 1}=10/3

3x + 3 = 10 x -10

7x = 13

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