SSC CGL Model Paper 9

Question : 52 of 100

Marks: +1, -0

LCM of two natural number is 410 and HCF is 41. How many sets of natural numbers are possible

Solution:

Two numbers be H.C.F × a, H.C.F × b
So, numbers be 41a, 41b
41 × 410 = 41a × 41b [LCM of two numbers × HCF of two numbers = product of two numbers]

10 = a × b

2 sets are possible

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