SSC CGL Model Paper 7

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Question : 71 of 100

Marks: +1, -0

Sin12°. Sin24°. Sin48°. Sin84° = ?

Cos20°. Cos40°. Cos60°. Cos80°
Sin20°. Sin40°. Sin60°. Sin80°
$3/16$
$1/16$

Solution:

Sin12°. Sin24°. Sin48°. Sin84° =

{( \sin 12 °\sin 48 °\sin 72 °)(\sin24°.\sin36°.\sin84°) }/{\sin72° . \sin36°}

=1/4\sin36°×1/4\sin72°

×1/{\sin72° . \sin36°}=1/16

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