SSC CGL Model Paper 5

Question : 52 of 100

Marks: +1, -0

\tan 5x. \tan3x. \tan2x = ?

Solution:

\tan 5x=\tan (3x+2x)

={\tan3x+\tan2x}/{1-\tan3x.\tan2x}

⇒

\tan5x -\tan5x. \tan3x. \tan2x

= \tan3x + \tan2x

⇒

\tan5x. \tan3x. \tan2x

= \tan5x -\tan3x -\tan2x

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