SSC CGL Model Paper 3

Join PQRST as shown in the fig.
We get a regular pentagon.
WKT
Interior angle of a regular pentagon = 108°
So, In ΔPAQ
∠APQ = ∠PQA = 72°
∴ ∠PAQ = 180° - 72 × 2 = 180° - 144 = 36°