SSC CGL Model Paper 3

Question : 62 of 100

Marks: +1, -0

In ΔABC of side

2√3

cm, 'P' is any point in the interior of ΔABC. In x,y, z are perpendicular distance of P from sides of the Δ, then x + y + z = ?

Solution:

Area of ΔABC = area of ΔAPB + area of ΔAPC + area of ΔBPC
⇒

√3/4(2√3)^2={x×2√3}/2+{y×2√3}/2

+{z×2√3}/2

⇒

√3/2×2√3= (x + y + z)

⇒x + y + z = 3\cm

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