SSC CGL Model Paper 3

Question : 60 of 100

Marks: +1, -0

In given fig. ABCDEF is a regular hexagon of side 16 cm, P, Q & R are the mid-points of side AB, CD & EF respectively. Then area of APQR is (in cm

^2

)

Solution:

In isosceles quad AFEB
∵ P & R are mid points of AB & FE respectively
S0,

PR = {AF+BE}/2

Clearly,

BE = 2×16 = 32

PR={32+16}/2=24

cm
Similarly, RQ = PQ = 24 cm
∴ Area of ΔPRQ =

√3/4×24×24

=144√3\cm^2

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