SSC CGL Model Paper 19

Question : 59 of 100

Marks: +1, -0

In the Given fig. If AB = AC = 8 cm, BC = 11 cm, BD = 7 cm then AD = ?

Solution:

drop AE ⊥ BC

\BE =11/2

\cos\B =\BE/\AB

=11/{2×8}={11/16}

\AE=√{256-121}/2=√135/2

\AE^2+\ED^2=\AD^2

135/4+2.25=\AD^2

\AD=6\cm

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