What is the value of 3/2(\frac{\cos39}{\sin51})-\sqrt{\sin^2 39+\sin^2 51} ?

Correct Answer is : Both 12 and 52

SSC CGL Model Paper 18

Question : 70 of 100

Marks: +1, -0

What is the value of

3/2({\cos39}/{\sin51})-√{\sin^2 39+\sin^2 51}\ ?

Solution:

3/2({\cos39}/{\sin51})-√{\sin^2 39+\sin^2 51} ?

=3/2[{\cos(90-41)}/{\sin51}]

-√{\sin^2 (90-51)+\sin^2 51}

=3/2[{{\sin51}/{\sin51}]-√{\cos^2 51+\sin^2 51}

=3/2×1-√1=3/2±1

On taking ‘+ ’ sign

=3/2+1=5/2

On taking '-' sign

3/2-1=1/2

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