SSC CGL Model Paper 18

Question : 59 of 100

Marks: +1, -0

A man makes four trips of equal distances. His speed on first trip was 60 km /hr and in each subsequent trip his speed was half of the previous trip. What is the average speed (in km/hr) of the man in these four trips?

16
30
28.125
27.5

Validate

Solution:

Let the distance of each trip = d km
Average speed

={4d}/{d/60+d/30+d/15+{2d}/15

={4d}/{{d+2d+4d+8d}/60}={4d×60}/{15d}

=240/15=16

km/h

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