SSC CGL Model Paper 17

Question : 63 of 99

Marks: +1, -0

A man covers a distance of 384 km in a certain time. If he decreases his speed by 16 km/hr the time he takes increases by 2 hours. What is the 75% of his original speed?

64 km/hr
48 km/hr
60 km/hr
70 km/hr

Validate

Solution:

Let the speed be S
ATQ,

384/{\S-16}-384/\S=2

384({\S-\S+16}/{\S^2-16\S})=2

384×8=\S^2-16\S

\S^2-16\S-384×8=0

\S(\S-64)+48(\S-64)=0

\S=64\km\/\hr

Now,

75/100×64=48\km\/\hr

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