If 6^\N = 279936, what is the value of 6^\K, where K + 3 = N ?

SSC CGL Model Paper 17

Question : 58 of 99

Marks: +1, -0

6^\N = 279936

, what is the value of

6^\K

, where K + 3 = N ?

Solution:

6^\K=6^{\N-3}=6^\N/216

=279936/216=1296

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