(\frac{1-\tan^2 1 5}{1+\tan^2 15})=?

SSC CGL Model Paper 11

Question : 62 of 100

Marks: +1, -0

({1-\tan^2 1 5}/{1+\tan^2 15})=?

Solution:

\cos {2\θ}={1-\tan^2 \θ}/{1+\tan^2 \θ}

∴\cos(2×15)°=\cos30°=√3/2

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