SSC CGL Model Paper 11

Question : 54 of 100

Marks: +1, -0

CB is a tangent of a circle with center O. AB is a diameter of circle. AC intersects the circle at E. If AE = 8cm and circumference of circle is

264/7

cm, then find the length of BC(in cm) ?

Solution:

2\π\r=264/7\cm

\r=6\cm

Let
CE = x

\BC^2 = x (8+x)

= (8+x)^2 -144

8x + x^2 = 64 + x^2 + 16x -144

80 = 8x ⇒ x = 10

\CB^2 = x × (8 + x) = 10 × 18

\CB = 6√5 \cm

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