SSC CGL Model Paper 10

Question : 69 of 100

Marks: +1, -0

tan 45°+ cosec 60° = ?

Solution:

\tan 45°+ \cosec 60°

=1+2/√3={√3+2} /√3

={√3+2} /√3 ×√3/√3={3+2√3}/3

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