SSC CGL Model Paper 1

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Question : 57 of 100

Marks: +1, -0

If

x ^p = y ^q = z^r

and

y/x = z/y

than

{pq+qr}/2

is equal to :

$r ^2$
pr
$p ^2$
pq

Solution:

x ^p = y ^q = z^r=k

So,

x = k^{1/p} ;y = k ^{1/q} ; z = k^{1/z}

ATQ,

y/x=z/y

⇒

k ^{1/q}/k ^{1/p}=k ^{1/r}/k ^{1/q}

⇒

k ^({1/q-1/p})=k ^({1/r-1/q})

⇒

1/q-1/p= {1/r-1/q}

⇒

2/q=1/r+1/p

⇒

2/q={p+r}/{pr}⇒{pq+qr}/2=pr

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