SSC CGL Model Paper 1

Question : 53 of 100

Marks: +1, -0

A number when successively divided by 3,4 and 5, leaves the respective remainder of 1,2 and 3. What will be the last remainder when such a least possible number is divided successively by 5, 4, and 3 ?

Validate

Solution:

For least possible number

Least possible number will be

= \{[(5×0+3)×4+2]×3+1\}⇒ 43

Now dividing successively by 5, 4 and 3

So, the last remainder is '2'.

Go to Question:

Prev Question

Next Question