SSC CGL 9 Aug 2015 Shift 1 Paper

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Question : 143 of 200

Marks: +1, -0

The numerical value of

{cos^2 45°}/{sin^2 60°}

+

{cos^2 60°}/{sin^2 45°}

-

{tan^2 30°}/{cot^2 45°}

-

{sin^2 30°}/{cot^2 30°}

is

1 $1/4$
$3/4$
$1/4$
$1/2$

Solution:

=

(1/√2)^2/(√3/2)^2

+

(1/2)^2/(1/√2)^2

-

(1/√3)^2/(1)^2

-

(1/2)^2/(√3)^2

=

1/2 × 4/3+1/4

× 2 -

1/3

× 1 -

1/{4×3}

=

2/3+1/2-1/3-1/{12}

=

{8+6-4-1}/{12}

=

9/{12}

=

3/4

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