SSC CGL 9 Aug 2015 Shift 1 Paper

Question : 140 of 200

Marks: +1, -0

A 10 metre long ladder is placed against a wall. It is inclined at an angle of 30° to the ground. The distance (in m) of the foot of the ladder from the wall is (Given

√3

= 1.732)

8.16
7.32
8.26
8.66

Validate

Solution:

AC = ladder = 10 metre
BC = ?
∠ABC = θ = 30°
From ΔABC ,
cos θ =

{BC}/{AC}

⇒ cos 30° =

{BC}/{10}

⇒

√3/2

{BC}/{10}

⇒ BC =

{10√3}/2

5√3

= 5 × 1.732
= 8.660 metre

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