SSC CGL 9 Aug 2015 Shift 1 Paper

Question : 135 of 200

Marks: +1, -0

The measure of an angle whose supplement is three times as large as its complement, is

Solution:

Let the required angle be x°.
According to the question,
180 – x = 3(90 – x )
⇒ 180 – x = 270 – 3x
⇒ 3x – x = 270 – 180
⇒ 2x = 90 ⇒ x =

{90}/2

= 45°

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