SSC CGL 9 Aug 2015 Shift 1 Paper

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Question : 101 of 200

Marks: +1, -0

In ΔABC, a line through A cuts the side BC at Δ such that BD : ΔC = 4 : 5. If the area of ΔABD = 60

cm^2

, then the area of ΔADC is

90 $cm^2$
50 $cm^2$
60 $cm^2$
75 $cm^2$

Solution:

Let, AE ⊥ BC
∴

{\Area \of Δ\ABD}/{\Area \of Δ\ADC}

=

{1/2 ×BD×AE}/{1/2×CD×AE}

⇒

{60}/{ΔADC}

=

{BD}/{CD}

⇒

{60}/{ΔADC}

=

4/5

⇒ ΔADC =

{6×5}/4

= 75 sq. cm.

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