SSC CGL 7 Sep 2016 Paper

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Question : 66 of 100

Marks: +1, -0

Δ ABC a right angled triangle has ∠B = 90° and AC is hypotenuse. D is its circumcentre and AB = 3 cm, BC = 4 cm. The value of BD is

3 cm.
4 cm.
2.5 cm.
5.5 cm.

Solution:

AD = DC = DB
In Δ ABC,
AC =

√{AB^2+BC^2}

=

√{3^2+4^2}

=

√{9+16}

=

√{25}

= 5 cm
∴ AD =

5/2

= 2.5 cm

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