SSC CGL 7 06 2019 Shift 2 Paper

Question : 66 of 100

Marks: +1, -0

In ΔABC, AD bisects ∠A and intersects BC at D. If BC = a, AC = b and AB = c, then BD = 7

Solution:

As AD is angle bisector.
So,

\ {B D}/{D C}=\ {c}/{b}

Now

\ {B C}/{B D}=\ {b+c}/{c}

⇒

\ {BD}=\ {\ {ac}}/{\ {b}+\ {c}}

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