SSC CGL 7 06 2019 Shift 2 Paper

Question : 64 of 100

Marks: +1, -0

The sides AB and AC of a ΔABC are extended to P and Q respectively. If the bisector of ∠PBC and ∠QCBinterest at O, and ∠A = 92°, then ∠BOC is equal to:

44°
46°
88°
42°

Validate

Solution:

\∠\ {BOC}=90-\ {\∠\ {A}}/{2}

=90-\ {92}/{2}=44^{0}

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