SSC CGL 7 06 2019 Shift 1 Paper

Question : 72 of 100

Marks: +1, -0

A journey of 96 km takes one hour less by a fast train (A) than by a slow train (B). If the average of B is 16 km/h less than that of A, then the average speed (in km/h) of A is:

Validate

Solution:

Let speed

A

x

than speed

B

x-16

ATQ

\ {96}/{x-16}-\ {96}/{x}=1

\⇒ x=48 \ {\km} \/ \ {\hr}

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