SSC CGL 7 06 2019 Shift 1 Paper

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Question : 66 of 100

Marks: +1, -0

The value of

6-6 \÷6 \ ×6+(6 \÷6

of 6

) \ ×6-\ (3 \ {2}/{3} \÷

\ {11}/{30}

of

{2}/{3}\ ) \÷5

is:

0
2
-1
-2

Solution:

6-6 \÷6 \× 6+(6 \÷6

of 6

) \× 6-\ (\ {11}/{3} \÷\ {22}/{90}\ ) \× \ {1}/{5}

\⇒ 6-1 \× 6+\ (\ {1}/{6}\ )

× 6-(15) \× \ {1}/{5}

\⇒ 0+1-3=-2

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