SSC CGL 7 06 2019 Shift 1 Paper

Question : 59 of 100

Marks: +1, -0

In a circle with centre O, PQR is a tangent at the point Q on it. AB is a chord in the circle parallel to the tangent such that ∠BQR = 70°. What is the measure of ∠AQB ?

40°
60°
55°
35°

Validate

Solution:

\ {PR} ∥ {AB}

\ {AQ}=\ {BQ} \ (

\Δ\ {ASQ} \≅ \Δ\ {BSQ})

And

\∠\ {QAB}=\∠\ {QBA}

Now,

\∠\ {RQB}=70°=\∠\ {QBS}

\ {\So}, \∠\ {QAB}=70°

\ {\Now}, \ {\In} \Δ\ {AQB}

70+\∠A Q B+70=180°

\∠\ {AQB}=40°

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