SSC CGL 6 Sep 2016 Paper

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Question : 59 of 100

Marks: +1, -0

If 4r = h +

√{r^2+h^2}

then r : h is ? (r ≠ 0)

17:8
8:17
8:15
15:8

Solution:

4r = h +

√{r^2+h^2}

⇒ 4r - h =

√{r^2+h^2}

On squaring both sides,

(4r-h)^2

=

(√{r^2+h^2})^2

⇒ 16

r^2 + h^2

- 8rh =

r^2+h^2

⇒

16r^2-r^2

= 8 rh ⇒

15r^2

= 8rh
⇒ 15r = 8h ⇒

r/h

=

8/{15}

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