{\cos ⁡20^{ \circ }}/{ \sin ⁡70^{ \circ }} + \frac{\cos ⁡\theta }{\sin (90^{ \circ }−\theta ) } = _______.

SSC CGL 6 Dec 2022 Shif 1 Paper

Question : 63 of 100

Marks: +1, -0

\;{\cos\;⁡20^{\;∘\;}}/{\ sin\;⁡70^{\;∘\;}}

\;{\cos\;⁡θ\;}/{sin\;(90^{\;∘\;}−θ ) }

= _______.

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