SSC CGL 6 Aug 2017 Shift 1 Paper

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Question : 63 of 100

Marks: +1, -0

Sum of a fraction and thrice of its reciprocal is

73/20

. What is the fraction?

$4/5$
$9/4$
$4/9$
$5/4$

Solution:

Let the fraction = x
According to the question,

x+3/x=73/20⇒ {x^2+3}/x=73/20

⇒

20x^2 + 60 = 73x

⇒

20x^2 - 7 3x+ 60 = 0

⇒

20x^2- 4 8x - 2 5 x + 60 = 0

⇒

4x(5x -1 2 ) - 5(5x -1 2 ) = 0

⇒

(4x - 5)(5x -1 2 ) = 0

∴

x=5/4\or12/5

Hence, required fraction

=5/4

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