SSC CGL 6 Aug 2017 Shift 1 Paper

Question : 22 of 100

Marks: +1, -0

If 8θ12δ6=60 and 13θ15δ11=74, then 18θ21δ15 = ?

Solution:

As,8 θ 12 δ 6

= 8 × 12 - ( 6 ) ^2

= 9 6 -3 6 = 6 0

and
13 θ15 δ11 =

1 3×1 5 - ( 11) ^2

= 195-121=74

Similarly, 18 θ 21 δ 15

= 1 8 × 2 1 -(1 5 )^2

= 3 7 8 -2 2 5 = [153]

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