SSC CGL 6 06 2019 Shift 2 Paper

Question : 61 of 100

Marks: +1, -0

If the 8-digit number 2074x4y2 is divisible by 88, then the value of (4x + 3y) is :

Solution:

no. is divisible by 88
so it is divisible by 8 and 11

=\ {4 y 2}/{8}

y=3,7

=x-4+6=x+2

So x should be 9

y=3

(4 x+3 y)

=4 \× 9+3 \× 3=36+9=45

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